R. Losno,
LISA, Universités
Paris 7 - 12, UMR 7583 CNRS
The objet cloud
What situation: Non polluted cloud, with or without dissolution of trace metals
Influence of trace metal
Why use trace metals into models?
Is it time consuming?
Examples:
Heterogeneous reactions (water-gas,
water-solid)
Homogeneous reactions within the waterNON
POLLUTED AREA REACTION SET
Reactants and products, mol.L1:
O3: 3.000E-10 H2O2: 2.800E-05 HO2: 0.000E+00
O2-: 0.000E+00 OH: 1.000E-14 H+: 1.000E-05
hv: 1.000E+00 O2: 3.000E-04 FeII: 2.000E-08
FeIII: 4.000E-08 MnII: 3.000E-09 MnIII: 0.000E+00
CuI: 0.000E+00 CuII:
1.000E-09
Constant (mol.L1):
H+: 1.000E-05 O3: 3.000E-10
Reactions:
(01) H2O2 + hv --> OH + OH k=5.700E-07
(02) HO2 + OH --> O2 k=7.000E+09
(03) O2- + OH --> O2 k=1.100E+10
(04) H2O2 + OH --> HO2 k=2.700E+07
(05) O3 + OH --> HO2 + O2- k=2.000E+09
(06) HO2 + HO2 --> H2O2 + O2 k=8.600E+05
(07) HO2 + O2- --> H2O2 + O2 k=1.000E+08
(08) H2O2 + HO2 --> OH + O2 k=5.000E-01
(09) H2O2 + O2- --> OH + O2 k=1.300E-01
(10) O3 + O2- --> OH + O2 + O2 k=1.500E+09
(11) OH + MnII --> MnIII k=3.400E+07
(12) HO2 + MnII --> MnIII + H2O2 k=6.000E+06
(13) O2- + MnII --> MnIII + H2O2 k=1.100E+08
(14) HO2 + MnIII --> MnII + O2 + H+ k=2.000E+04
(15) O2- + MnIII --> MnII + O2 k=1.500E+08
(16) H2O2 + MnIII --> MnII + HO2 + H+ k=3.200E+04
(17) HO2 + FeIII --> FeII + H+ + O2 k=2.000E+04
(18) O2- + FeIII --> FeII + O2 k=1.500E+08
(19) hv + FeIII --> FeII + OH k=5.900E-04 (at pH 5)
(20) HO2 + FeII --> FeIII + H2O2 k=1.200E+06
(21) O2- + FeII --> FeIII + H2O2 k=1.000E+07
(22) OH + FeII --> FeIII k=3.000E+08
(23) O3 + FeII --> FeIII + OH + O2 k=1.700E+05
(24) FeII + MnIII --> FeIII + MnII k=2.100E+04
(25) H2O2 + FeII --> FeIII + OH k=6.010E+01
(26) O2 + FeII --> FeIII + O2- k=7.900E-04
(27) FeIII + CuI --> FeII + CuII k=1.000E+07
(28) OH + CuI --> CuII k=3.000E+08
(29) HO2 + CuI --> CuII + H2O2 k=1.500E+09
(30) O2- + CuI --> CuII + H2O2 k=1.000E+10
(31) H2O2 + CuI --> CuII + OH k=4.000E+05
(32) MnIII + CuI --> CuII + MnII k=2.100E+04
(33) HO2 + CuII --> CuI + O2 + H+ k=1.000E+08
(34) O2- + CuII --> CuI
+ O2 k=5.000E+09
Acid/Base Couples:
HO2 / O2- pKa= 4.68
Simple system without trace metal dissolution
Simple system with trace amounts of
Fe, Cu and Mn
Short system:
(01) H2O2 + hv --> OH + OH k=5.700E-07
(04) H2O2 + OH --> HO2 k=2.700E+07
(18) O2- + FeIII --> FeII + O2 k=1.500E+08
(19) hv + FeIII --> FeII + OH k=5.900E-04 at pH 5
(25) H2O2 + FeII --> FeIII + OH k=6.010E+01
(31) H2O2 + CuI --> CuII + OH k=4.000E+05
(34) O2- + CuII --> CuI
+ O2 k=5.000E+09
Methanol: 1.000E-07 mol.L1
(39) OH + CH3OH --> CH2O k=9.700E+08
(40) OH + CH2O --> HCOOH + HO2 k=7.700E+08
(41) OH + HCOOH --> HO2 k=1.100E+08
(42) OH + HCOO- --> HO2 k=3.100E+09
OH concentration variations
HO2 concentration variations
Iron and HO2 with methanol
Methanol oxidation
Adding trace
metals completely change the
reaction scheme
Adding trace
metals make the system very less
sensitive to other reactive species
Adding trace
metals let hope to use photostationary
equilibrium instead of kinetics
The trace
metal amounts injected in the
model are an average
value measured in rainwater.
We must go further to include particulate-dissolved
dynamic modelisation.